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From a circular sheet of radius $4\ cm$, a circle of radius $3\ cm$ is removed. Find the area of the remaining sheet. $(Take\ \pi=3.14)$
Given:
Radius of circular sheet$=4\ cm$.
Radius of the circle removed$=3\ cm$.
To do:
We have to find the area of the remaining sheet.
Solution:
The area of the circular sheet with $4\ cm$ radius $=\pi (4)^2=16 \pi$
The area of the circular sheet with $3\ cm$ radius $=\pi (3)^2=9 \pi$
Area of the remaining sheet$=$Area of the circular sheet$-$Area of the circle removed
$=16 \pi-9 \pi$
$=7 \pi$
$=7\times3.14$
$=21.98\ cm^2$
The area of the remaining sheet is $21.98\ cm^2$.
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