For the following APs, write the first term and the common difference:
,b>(i) $3, 1, -1, -3, ……$
(ii) $-5, -1, 3, 7, ……$
(iii) $\frac{1}{3}, \frac{5}{3}, \frac{9}{3}, \frac{13}{3}, ……..$
(iv) $0.6, 1.7, 2.8, 3.9, ……$
To do:
We have to write the first term and common difference of the given A.P in each case.
Solution:
(i) Given A.P. is $3,\ 1,\ −1,\ −3,......$
First term $a=3$
And common difference $d=a_2−a_1$
$=1−3$
$=−2$
Therefore, the first term is $3$ and the common difference is $-2$.
(ii) $-5, -1, 3, 7, ……$
In the given A.P.,
$a_1=-5, a_2=-1, a_3=3$
Therefore,
First term $a=a_1=-5$ Common difference $d=a_2-a_1=-1-(-5)=-1+5=4$.
The first term $a$ is $-5$ and the common difference $d$ is $4$.
(iii) $\frac{1}{3}, \frac{5}{3}, \frac{9}{3}, \frac{13}{3}, ……..$
In the given A.P.,
$a_1=\frac{1}{3}, a_2=\frac{5}{3}, a_3=\frac{9}{3}$
Therefore,
First term $a=a_1=\frac{1}{3}$
Common difference $d=a_2-a_1=\frac{5}{3}-\frac{1}{3}=\frac{5-1}{3}=\frac{4}{3}$.
The first term $a$ is $\frac{1}{3}$ and the common difference $d$ is $\frac{4}{3}$.
(iv) $0.6, 1.7, 2.8, 3.9, ……$
In the given A.P.,
$a_1=0.6, a_2=1.7, a_3=2.8$
Therefore,
First term $a=a_1=0.6$ Common difference $d=a_2-a_1=1.7-0.6=1.1$.
The first term $a$ is $0.6$ and the common difference $d$ is $1.1$.
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