Five coins were simultaneously tossed 1000 times and at each toss the number of heads were observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.
Number of heads per toss | Number of tosses |
---|
0 | 38 |
1 | 144 |
2 | 342 |
3 | 287 |
4 | 164 |
5 | 25 |
Total | 1000 |
"
Given:
Five coins were simultaneously tossed 1000 times and at each toss the number of heads were observed.
To do:
We have to find the mean number of heads per toss.
Solution:
Number of heads per tosses ($x_i$) | Number of tosses ($f_i)$ | $x_i \times\ f_i$ |
0 | 38 | 0 |
1 | 144 | 144 |
2 | 342 | 684 |
3 | 287 | 861 |
4 | 164 | 656 |
5 | 25 | 125 |
Total | 1000 | 2470 |
We know that,
Mean$=\frac{\sum fx}{\sum f}$
Therefore,
Mean $=\frac{2470}{1000}$
$=2.47$
The mean number of heads per toss is $2.47$.
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