Find the value of $(5x^6) \times (-1.5x^2y^3) \times (-12xy^2)$ when $x = 1, y = 0.5$.

AcademicMathematicsNCERTClass 8

Given:

$(5x^6) \times (-1.5x^2y^3) \times (-12xy^2)$

To do:

We have to find the value of $(5x^6) \times (-1.5x^2y^3) \times (-12xy^2)$ when $x = 1, y = 0.5$.

Solution:

$(5 x^{6}) \times(-1.5 x^{2} y^{3}) \times(-12 x y^{2})=5 \times(-1.5) \times(-12)\times x^{6} \times x^{2} \times x \times y^{3} \times y^{2}$

$=90 \times x^{6+2+1} \times y^{3+2}$

$=90 \times x^{9} y^{5}$

$=90\times (1)^{9} \times(0.5)^{5}$

$=90 \times 1 \times 0.03125$

$=2.8125$

raja
Updated on 10-Oct-2022 13:19:29

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