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Find the sum of :
(a) 137 and $ -354 $
(b) $โ 52$ and 52
(c) $โ 312$, 39 and 192
(d) $โ 50, โ 200$ and 300
To do :
We have to find the given sums.
Solution :
We know that,
$(+) \times (-) = (-)$
$(+) \times (+) = (+)$
$(-) \times (-) = (+)$
$(-) \times (+) = (-)$
(a) $137+(-354) = 137-354$
$=-(354-137)$
$= -217$
Therefore,
The sum of $137$ and $(-354)$ is $-217$.โโ
(b) $-52+ 52 = 52-52$
$= 0$
Therefore,
The sum of $-52$ and $52$ is $0$.โโ
(c) $(-312) + (+39) + (+192) = -312+39+192$
$=-312+231$
$=-(312-231)$
$= -81$
Therefore,
The sum of $-312, 39$ and $192$ is $-81$.โโ
(d) $(-50) + (-200) + (+300) = -50-200+300$
$=-(50+200)+300$
$=-250+300$
$=300-250$
$= 50$
Therefore,
The sum of $-50, -200$ and $300$ is $50$.โโ
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