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Find the product, using suitable properties:
(a) $26\times(- 48) + (- 48)\times(-36)$
(b) $8\times53\times(-125)$
(c) $15\times(-25)\times(- 4)\times(-10)$
(d) $(- 41)\times102$
(e) $625\times(-35) + (- 625)\times65$
(f) $7\times(50-2)$
(g) $(-17)\times(-29)$
(h) $(-57)\times(-19) + 57$
To do:
We have to find the product, using suitable properties in each case.
Solution:
(a) $26\times(-48)+(-48)\times(-36)$
Using distributive property, we get,
$(a\times b)+(b\times c)=b\times(a+c)$
$26\times(-48)+(-48)\times(-36)= (-48)\times[26+(-36)]$
$= (-48)\times[26 - 36]$
$= (-48)\times(-10)$
$= 480$
(b) $8\times53\times(-125)$
Using associative property, we get,
$(a\times b)\times c=a\times(b\times c)$
$8\times53\times(-125)= 53\times(8\times-(125))$
$= 53\times(-1000)$
$=-53000$
(c) $15\times(-25)\times( -4)\times(-10)$
Using associative property, we get,
$15\times(-25)\times( -4)\times(-10)= 15\times[(-25)\times(-4)\times(-10)]$
$= 15\times[(100)\times(-10)]$
$= 15\times(-1000)$
$= -15000$
(d) $(-41)\times102$
Using distributive law, we get,
$(-41)\times102= (-41)\times(100+2)$ $[a\times(b+c)]=(a\times b+a\times c)$
$= (-41)\times100+(-41)\times2$
$= -4100 - 82$
$= -4182$
(e) $625 \times(-35)\times(-625)\times65$
Using distributive property, we get,
$625 \times(-35)\times(-625)\times65= 625\times[(-35)+(-65)]$ $[a\times b+a\times c=a(b+c)]$
$= 625\times[-35 - 65]$
$= 625\times[-100]$
$= -62500$
(f) $7\times(50 - 2)$
Using distributive property, we get,
$7\times(50 - 2)= 70\times(50 -2)$ $[a\times(b - c)=(a\times b) - (a\times c)]$
$= [(7\times50) - (7\times2)]$
$= 350 - 14$
$= 336$
(g) $(-17)\times(-29)$
Using distributive property, we get,
$(-17)\times(-29)= (-17)\times[(-30)+1]$ $[a\times (b+c)=a\times b+a\times c]$
$= (-17)\times(-30)+(-17)\times1$
$= 510+(-17)$
$= 493$
(h) $(-57)\times(-19)+57$
Using distributive property, we get,
$(-57)\times(-19)+57= (-57)\times(-19)+57\times1$ $[a\times b+a\times c=a(b+c)]$
$= 57\times(19+1)$
$= 57\times20$
$= 1140$