Find the product:
$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$
$(ii)$. $\frac{3}{10}\times(-9)$
$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$
$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$
$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$
$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$

AcademicMathematicsNCERTClass 7

Given: 
$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$

$(ii)$. $\frac{3}{10}\times(-9)$

$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$

$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$ 

$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$

$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$


To do: To find the product of the given expression.


Solution:


$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$

$=\frac{9\times(-7)}{2\times4}$

$=-\frac{63}{8}$

$=-7\frac{7}{8}$

$(ii)$. $\frac{3}{10}\times(-9)$

$=-\frac{27}{10}$

$=-2\frac{7}{10}$


$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$

$=\frac{(-6)\times9}{5\times11}$

$=-\frac{54}{55}$

$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$

$=\frac{3\times(-2)}{7\times5}$ 

$=-\frac{6}{35}$


$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$

$=\frac{3\times2}{11\times5}$ 
 
$=\frac{6}{55}$

$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$

$=\frac{3\times(-5)}{(-5)\times3}$

$=\frac{-15}{-15}$

$=1$
raja
Updated on 10-Oct-2022 13:35:25

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