Find the number from each of the following expanded forms:
$(a)$. $8\times10^4+6\times10^3+0\times10^2+4\times10^1+5\times10^0$
$(b)$. $4\times10^4+5\times10^3+3\times10^2+2\times10^0$
$(c)$. $3\times10^4+7\times10^2+5\times10^0$
$(d)$. $9\times10^5+2\times10^2+3\times10^1$

AcademicMathematicsNCERTClass 7

Given:

$(a)$. $8\times10^4+6\times10^3+0\times10^2+4\times10^1+5\times10^0$

$(b)$. $4\times10^5+5\times10^3+3\times10^2+2\times10^0$

$(c)$. $3\times10^4+7\times10^2+5\times10^0$

$(d)$. $9\times10^5+2\times10^2+3\times10^1$


To do: To find the number from each of the following expanded forms.

Solution:
$(a)$. $8\times10^4+6\times10^3+0\times10^2+4\times10^1+5\times10^0$
 
$=8\times10000+6\times1000+0\times100+4\times10+5\times1$

$=80000+6000+0+40+5$

$=86,045$


$(b)$. $4\times10^5+5\times10^3+3\times10^2+2\times10^0$
 

$=4\times100000+5\times1000+3\times100+2\times1$

$=400000+5000+300+2$

$=405302$


$(c)$. $3\times10^4+7\times10^2+5\times10^0$

$=3\times10000+7\times100+5\times1$

$=30000+700+5$

$=30705$


$(d)$. $9\times10^5+2\times10^2+3\times10^1$
 
$=9\times100000+2\times100+3\times10$

$=900230$
raja
Updated on 10-Oct-2022 13:38:51

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