Find the following product.
$(7ab) \times (-5ab^2c) \times (6abc^2)$

AcademicMathematicsNCERTClass 8

Given:

$(7ab) \times (-5ab^2c) \times (6abc^2)$

To do:

We have to find the given product.

Solution:

$(7ab) \times (-5ab^2c) \times (6abc^2) = 7 \times (-5) \times 6 \times a \times a \times a \times b \times b^2 \times b \times c \times c^2$

$=-210 \times a^{1+1+1} \times b^{1+2+1} \times c^{1+2}$

$=-210 \times a^3b^4c^3$

raja
Updated on 10-Oct-2022 13:19:29

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