Find the area of the following circles, given that: $(Take\ \pi=\frac{22}{7})$
$(a)$ radius = 14 mm
$(b)$ diameter = 49 m
$(c)$ radius = 5 cm

$(a)$. Here, $r=14\ mm$

Area of the circle$=\pi r^2$

$=\pi\times14\times14$

$=\frac{22}{7}\times14\times14$

$=616\ mm^2$

$(b)$. Here, diameter$=49\ m$

$r=\frac{49}{2}\ m$

Area$=\pi r^2$

$=\frac{22}{7}\times\frac{49}{2}\times\frac{49}{2}$ 

$=\frac{3773}{2}\ m^2$

$=1886.5\ m^2$ 

$(c)$. Here, radius$=5\ cm$

Area$=\pi r^2$

$=\frac{22}{7}\times5\times5$

$=\frac{550}{7}\ m^2$

$=78.57\ cm^2$

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Updated on: 10-Oct-2022

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