- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

# Find the area of rectangles with the following pairs of monomials as their lengths and breadths respectively:

**(1)** $(10m, 5n)$

**(2)** $(20x^2 , 5y^2)$

**Given:**

Lengths and breadths of rectangles are as follows:

$(10m, 5n)$

$(20x^2, 5y^2)$

**To do:**

We have to find the area of rectangles.

**Solution:**

We know that,

Area of a rectangle of length $l$ and breadth $b$ is $lb$.

Therefore,

Area of the rectangle with $(10m, 5n)$ as its measurements is,

$A=10m \times 5n$

$=50mn$

Area of the rectangle with $(20x^2, 5y^2)$ as its measurements is,

$A=20x^2 \times 5y^2$

$=100x^2y^2$

- Related Questions & Answers
- Sum of the series 2^0 + 2^1 + 2^2 +...+ 2^n in C++
- Sum of series 1^2 + 3^2 + 5^2 + . . . + (2*n – 1)^2
- Sum of series 1^2 + 3^2 + 5^2 + . . . + (2*n - 1)^2 in C++
- Sum of the series 1 + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n) in C++
- Find Sum of Series 1^2 - 2^2 + 3^2 - 4^2 ... upto n terms in C++
- Sum of the series 1 / 1 + (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + … + upto n terms in C++
- Find sum of Series with n-th term as n^2 - (n-1)^2 in C++
- Python Program for Find sum of Series with the n-th term as n^2 – (n-1)^2
- C/C++ Program to Find the sum of Series with the n-th term as n^2 – (n-1)^2
- C++ program to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n
- Java Program to Find sum of Series with n-th term as n^2 – (n-1)^2
- Sum of the Series 1/(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + ... in C++
- C/C++ Program to Find sum of Series with n-th term as n power of 2 - (n-1) power of 2
- Sum of the series 1^1 + 2^2 + 3^3 + ... + n^n using recursion in C++
- C++ program to find the sum of the series 1/1! + 2/2! + 3/3! + 4/4! +…….+ n/n!
- Sum of the series 2 + (2+4) + (2+4+6) + (2+4+6+8) + ... + (2+4+6+8+...+2n) in C++

Advertisements