Find
(a) $ (-7)-8-(-25) $
(b) $(– 13) + 32 – 8 – 1$
(c) $(– 7) + (– 8) + (– 90)$
(d) $50 – (– 40) – (– 2)$

To do :

We have to fill in the blank.

Solution :

We know that,

$(+) \times (-) = (-)$

$(+) \times (+) = (+)$

$(-) \times (-) = (+)$

$(-) \times (+) = (-)$

(a) $(-7)-8-(-25)=-7-8+25$

$=-(7+8)+25$

$=-15+25$

$=25-15$

$=10$

Therefore,

\( (-7)-8-(-25)=10 \)

(b) $(-13)+32-8-1=-13+32-8-1$

$=32-(13+8+1)$

$=32-22$

$=10$

Therefore,

\( (-13)+32-8-1=10 \)

(c) $(-7)+(-8)+(-90)=-7-8-90$

$=-(7+8+90)$

$=-105$

Therefore,

\( (-7)+(-8)+(-90)=-105 \)

(d) $50-(-40)-(-2)=50+40+2$

$=92$

Therefore,

\( 50-(-40)-(-2)=92 \)

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Updated on: 10-Oct-2022

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