Express in kg:
(i) $200$ g
(ii) $3470$ g
(iii) $4$ kg $8$ g


Given:

(i) $200$ g   

(ii) $3470$ g   

(iii) $4$ kg $8$ g

To do:

We have to express the weights in kg.

Solution:

$1000\ g =1\ kg$

This implies,

$1\ g = \frac{1}{1000}\ kg$

Therefore,

(i) $200 g$

$200\ g = 200\times \frac{1}{1000}\ kg$

$=\frac{200}{1000}\ kg$

$=0.2\ kg$

(ii) $3470\ g$

$3470\ g=3470 \times \frac{1}{1000}\ kg$

$3470\ g=\frac{3470}{1000}\ kg$

$=3.47\ kg$

(iii) $4\ kg\ 8\ g$

$4\ kg\ 8\ g=4\ kg+8\ g$

$4\ kg\ 8\ g=4\ kg+8\times\frac{1}{1000}\ kg$

$4\ kg\ 8\ g=4\ kg+0.008\ kg$

$4\ kg\ 8\ g=4.008\ kg$

Updated on: 10-Oct-2022

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