Explain, why $∆ABC ≅ ∆FED$.
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Given: Two triangles $∆ABC$ and $∆FED$.

To do: To explain that $∆ABC ≅ ∆FED$.

Solution:

Given $\angle A\cong\angle F$

$BC=ED$

$\angle B=\angle E$

In $\triangle ABC$ and $\triangle FED$

$\angle B=\angle E=90^{\circ}$

$\angle A=\angle F$

$BC=ED$

Therefore, $\triangle ABC\cong\triangle FED$          [RHS congruence rule]
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