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# Explain, why $âˆ†ABC â‰… âˆ†FED$.

"

**Given:**Two triangles $âˆ†ABC$ and $âˆ†FED$.

**To do:**To explain that $âˆ†ABC ≅ âˆ†FED$.

**Solution:**

Given $\angle A\cong\angle F$

$BC=ED$

$\angle B=\angle E$

In $\triangle ABC$ and $\triangle FED$

$\angle B=\angle E=90^{\circ}$

$\angle A=\angle F$

$BC=ED$

Therefore, $\triangle ABC\cong\triangle FED$ [RHS congruence rule]

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