Evaluate: $(2.3a^5b^2) \times (1.2a^2b^2)$ when $a = 1, b = 0.5$.

AcademicMathematicsNCERTClass 8

Given:

$(2.3a^5b^2) \times (1.2a^2b^2)$ 

To do:

We have to evaluate $(2.3a^5b^2) \times (1.2a^2b^2)$ when $a = 1, b = 0.5$.

Solution:

$(2.3 a^{5} b^{2}) \times(1.2 a^{2} b^{2})=2.3 \times 1.2 \times a^{5} \times a^{2} \times b^{2} \times b^{2}$

$=2.76 \times a^{5+2} \times  b^{2+2}$

$=2.76 \times a^{7} \times b^{4}$

$=2.76\times(1)^{7} \times(0.5)^{4}$

$=\frac{276}{100} \times 1 \times(\frac{1}{2})^{4}$

$=\frac{276}{100} \times \frac{1}{16}$

$=\frac{69}{400}$

raja
Updated on 10-Oct-2022 13:19:29

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