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# Draw an angle of $ 40^{\circ} $. Copy its supplementary angle.

**To do:**

We have to draw an angle of $40^o$ and its supplementary angle.

**Solution:**

__Steps of construction:__

(i) Let us draw a line $l$ and mark points $P$, $O$ and $Q$ on it. Now, let us place the centre of the protractor on the point $O$ and mark a point $A$ at an angle of measure of $40^o$ with the line $l$.

(ii) Now, let us join point $A$ and point $O$. Therefore, $\overline{AB}$ has an angle of measure of $40^o$ with the line $l$.

(iii) Hence, $\angle{POA}$ is the supplementary angle of $40^o$.

(iv) Now, by taking compasses with any radius let us draw an arc from point $O$ inside the $\angle{POA}$ and mark the points of intersection with the line $l$ and $\overline{OA}$ as points $B$ and $C$ respectively.

(v) Now, let us draw another line $m$ and mark a point $S$ on it.

(vi) Now, by taking compasses with the same radius as before let us draw an arc from the point $S$ and mark the point of intersection of the arc with line $m$ as $T$.

(vii) Now, by taking compasses with the measure of length from point $B$ to $C$ let us draw an arc from point $C$ and mark the point of intersection of this arc with the previous arc as point $R$.

(viii) Now, let us join the point $R$ and the point $S$. Therefore, the required supplementary angle of an angle $40^o$ is formed.

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