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Do the following equations represent a pair of coincident lines? Justify your answer.
$ -2 x-3 y=1 $
$ 6 y+4 x=-2 $
Given :
The given pair of equations is,
\( -2 x-3 y=1 \)
\( 6 y+4 x=-2 \)
To find :
We have to find whether the given pair of equations represent a pair of coincident lines.
Solution:
We know that,
The condition for coincident lines is
$\frac{a_1}{a_2}=\frac{b_1}{b_2}≠\frac{c_1}{c_2}$
\( -2 x-3 y-1=0 \)
\( 6 y+4 x+2=0 \)
Here,
$a_1=-2, b_1=-3, c_1=-1$
$a_2=4, b_2=6, c_2=2$
Therefore,
$\frac{a_1}{a_2}=\frac{-2}{4}=\frac{-1}{2}$
$\frac{b_1}{b_2}=\frac{-3}{6}=\frac{-1}{2}$
$\frac{c_1}{c_2}=\frac{-1}{2}$
Here,
$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$
Hence, the given pair of linear equations represent coincident lines.
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