$DL$ and $BM$ are the heights on sides $AB$ and $AD$ respectively of parallelogram $ABCD$ $(Fig 11.24)$. If the area of the parallelogram is $1470\ cm^2$, $AB = 35\ cm$ and $AD = 49\ cm$, find the length of $BM$ and $DL$.
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Given:
Area of parallelogram $=1470\ cm^2$
$AB=35\ cm$ and $AD=49\ cm$
To do:
We have to find the length of $BM$.
Solution:
We know that,
Area of parallelogram of base b and height h $=b\times h$
This implies,
$1470=49\times BM$
$BM= \frac{1470}{49}\ cm$
$BM=30\ cm$
Therefore, the length of BM is 30 cm.
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