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Find the cost of polishing a circular table top of diameter 1.6 m, if the rate of polishing is Rs. $15\ /m^2$. $(\pi = 3.14 )$
Given:
Diameter of the table top$=1.6\ m$.
The rate of polishing $= Rs.\ 15/m^2$
To do:
We have to find the cost of polishing the circular table top.
Solution:
Radius of the table top$=\frac{1.6}{2}\ m=0.8\ m$.
Area of the table top$=\pi (radius)^2$
$=3.14\times(0.8)^2$
$=3.14\times0.64$
$=2.0096\ m^2$ Therefore, Cost of polishing the table top$=Area\ of\ the\ table\ top\times\ Rate\ of\ polishing$ $=Rs.\ 2.0096 \times15$
$=Rs.\ 30.144$
The cost of polishing the table top is Rs. 30.144.
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