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# Curved surface area of a right circular cylinder is $ 4.4 \mathrm{~m}^{2} $. If the radius of the base of the cylinder is $ 0.7 \mathrm{~m} $, find its height.

Given:

The curved surface area of a right circular cylinder is $4.4\ m^2$.

The radius of the base of the cylinder is $0.7\ m$.

To do:

We have to find its height.

Solution:

The curved surface area of the cylinder $= 4.4\ m^2$

Radius of the base $(r) = 0.7\ m$

Therefore,

Height of the cylinder $=\frac{\text { Curved surface area }}{2 \pi r}$

$=\frac{4.4 \times 7}{2 \times 22 \times 0.7}$

$=\frac{44 \times 7 \times 10}{10 \times 2 \times 22 \times 7}$

$=1 \mathrm{~m}$

The height of the cylinder is $1\ m$.

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