Construct $∆XYZ$ in which $XY=4.5\ cm,\ YZ=5\ cm$ and $ZX=6\ cm$.

Follow the steps given below:

• Draw a line segment YZ of length 5 cm.
• From Y, we need a point X at a distance of 4.5 cm. So, with Y as the center, draw an arc with a radius of 4.5 cm. From Z, point X is at a distance of 6 cm.
• So, with Z as the center, draw an arc of a radius of 6 cm.
• X has to be on both the arcs drawn.
• So, it is the point of intersection of arcs. Mark the point of intersection of arcs as X.
• Join XY and XZ.

Thus, $\triangle XYZ$ is the required triangle.

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Updated on 10-Oct-2022 13:35:44

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