# Construct an isosceles right-angled triangle $ABC$, where $m\angle ACB = 90^{\circ}$ and $AC = 6\ cm$.

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Given: In an isosceles right-angled triangle $ABC$, where $m\angle ACB = 90^{\circ}$ and $AC = 6\ cm$.

To do: To construct $\triangle ABC$.

Steps of construction:

• At first, let us draw a line segment $AC=6\ cm$.
• At $C$, draw a perpendicular such that $CX\perp AC$.
• Let us assume $C$ as a center and draw an arc of radius $6\ cm$ that intersects $CX$ at point $B$.
• Now, Join $B$ and $A$.

$\triangle ABC$ is the required isosceles right-angle triangle.
Updated on 10-Oct-2022 13:35:25