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# Construct an isosceles right-angled triangle $ABC$, where $m\angle ACB = 90^{\circ}$ and $AC = 6\ cm$.

**Given:**In an isosceles right-angled triangle $ABC$, where $m\angle ACB = 90^{\circ}$ and $AC = 6\ cm$.

**To do:**To construct $\triangle ABC$.

**Steps of construction:**

- At first, let us draw a line segment $AC=6\ cm$.
- At $C$, draw a perpendicular such that $CX\perp AC$.
- Let us assume $C$ as a center and draw an arc of radius $6\ cm$ that intersects $CX$ at point $B$.
- Now, Join $B$ and $A$.

$\triangle ABC$ is the required isosceles right-angle triangle.

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