Construct an isosceles right-angled triangle $ABC$, where $m\angle ACB = 90^{\circ}$ and $AC = 6\ cm$.
Given: In an isosceles right-angled triangle $ABC$, where $m\angle ACB = 90^{\circ}$ and $AC = 6\ cm$.
To do: To construct $\triangle ABC$.
Steps of construction:
- At first, let us draw a line segment $AC=6\ cm$.
- At $C$, draw a perpendicular such that $CX\perp AC$.
- Let us assume $C$ as a center and draw an arc of radius $6\ cm$ that intersects $CX$ at point $B$.
- Now, Join $B$ and $A$.
$\triangle ABC$ is the required isosceles right-angle triangle.
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