Complete Table 4.1 on the basis of information available in the symbols given below
(a) 3517Cl
(b) 126C
(c) 8135Br
Elementnpnn
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AcademicChemistryNCERTClass 9

Elementnpnn
Cl1718
C66
Br3546

[Extra information: p of Cl= Atomic number =17

​nn of Cl= Mass number - Atomic number =A−Z=35−17=18

p of C= Atomic number =6

nn  of C= Mass number - Atomic number = A−Z = 12−6 = 6

n of Br= Atomic number =35

n n of Br= Mass number - Atomic number = A−Z = 81−35 = 46]

raja
Updated on 10-Oct-2022 13:32:33

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