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# Choose the correct answer from the given four options:

The first four terms of an AP, whose first term is $ -2 $ and the common difference is $ -2 $, are

**(A) $ -2,0,2,4 $**

**(B)**$ -2,4,-8,16 $

**(C)** $ -2,-4,-6,-8 $

**(D)** $ -2,-4,-8,-16 $

**(B)**$ -2,4,-8,16 $

**(C)**$ -2,-4,-6,-8 $

**(D)**$ -2,-4,-8,-16 $

Given:

First term, $a=-2$ and common difference $d=-2$.

To do:

We have to find the first four terms of the given A.P.

Solution:

First term$( a)=-2$

Common difference$( d)=-2$

$\therefore\ 2^{nd}$ term$=a+d=-2-2=-4$

$\Rightarrow\ 3^{rd}$ term$a+2d=-2+2( -2)=-6$

$\Rightarrow\ 4^{th}$ term $a+3d=-2+3( -2)=-8$

Therefore, the A.P. is $-2,\ -4,\ -6,\ -8,$ ......

The first four terms of the given AP are $-2, -4, -6$ and $-8$.

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