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Choose the correct answer from the given four options:
The first four terms of an AP, whose first term is $ -2 $ and the common difference is $ -2 $, are
(A) $ -2,0,2,4 $
(B)$ -2,4,-8,16 $
(C) $ -2,-4,-6,-8 $
(D) $ -2,-4,-8,-16 $
Given:
First term, $a=-2$ and common difference $d=-2$.
To do:
We have to find the first four terms of the given A.P.
Solution:
First term$( a)=-2$
Common difference$( d)=-2$
$\therefore\ 2^{nd}$ term$=a+d=-2-2=-4$
$\Rightarrow\ 3^{rd}$ term$a+2d=-2+2( -2)=-6$
$\Rightarrow\ 4^{th}$ term $a+3d=-2+3( -2)=-8$
Therefore, the A.P. is $-2,\ -4,\ -6,\ -8,$ ......
The first four terms of the given AP are $-2, -4, -6$ and $-8$.
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