# Choose the correct answer from the given four options in the following questions:The zeroes of the quadratic polynomial $x^{2}+99 x+127$ are(A) both positive(B) both negative,b>(C) one positive and one negative(D) both equal

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Given:

Quadratic polynomial $x^2+99x+127$.

To do:

We have to find the nature of the zeroes of the quadratic polynomial $x^2+99x+127$.

Solution:

In a quadratic expression $ax^2+bx+c$, if $a,\ b,\ c$ will have the same sign

then the both zeroes of the expression are negative

On comparing given expression $x^2+99x+127$ with $ax^2+bx+c$,

$a=1,\ b = 99,\ c = 127$

All have positive sign.

Therefore, both the zeroes of the given expression have negative sign.

Updated on 10-Oct-2022 13:27:08