# Choose the correct answer from the given four options in the following questions:The quadratic equation $2 x^{2}-\sqrt{5} x+1=0$ has(A) two distinct real roots(B) two equal real roots(C) no real roots(D) more than 2 real roots

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To do:

We have to find the correct answer.

Solution:

$2 x^{2}-\sqrt{5} x+1=0$

Comparing with $a x^{2}+b x+c=0$, we get,

$a=2, b=-\sqrt{5}$ and $c=1$

Therefore,

$D =b^{2}-4 a c$

$=(-\sqrt{5})^{2}-4 \times(2) \times(1)$

$=5-8$

$=-3<0$

The discriminant is negative.

This implies, the quadratic equation $2 x^{2}-\sqrt{5} x+1=0$ has no real roots.

Updated on 10-Oct-2022 13:27:26