Choose the correct answer from the given four options:
In an AP, if $ a=3.5, d=0, n=101 $, then $ a_{n} $ will be
(A) 0
(B) $ 3.5 $
,b>(C) $ 103.5 $
(D) $ 104.5 $

Given: 

In an AP, $a = 3.5,\ d = 0,\ n = 101$.

To do: 

We have to find $a_n$.

Solution:

$a = 3.5,\ d = 0,\ n = 101$

Therefore,

$a_n=a+( n-1)d$

$\Rightarrow a_n=3.5+( 101-1)0$

$\Rightarrow a_n=3.5+0$

$\Rightarrow a_n=3.5$

Hence, $a_n=3.5$.