Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Given:

Baichung's Father is 26 years younger than Baichung's Grandfather and 29 years older than Baichung.

The sum of the ages of all the three is 135. 

To do :

We have to find the ages of each of them.

Solution :

Let the age of Baichung be $x$ and the age of the grandfather be $y$.

This implies,

Age of Baichung's father $= x+29 = y-26$

$y = x+29+26 = x+55$

The sum of the ages of all the three $= 135$

$x+(x+29)+y = 135$

$x+x+29+x+55 = 135$

$3x+84 = 135$

$3x = 135-84$

$3x = 51$

$x = \frac{51}{3}$

$x = 17$

$x+29 = 17+29=46$

$y = x+55 = 17+55=72$

The age of Baichung is 17 years.

The age of Baichung's father is  46 years.

The age of Baichung's Grandfather is 72 years.