J.R. S. answered • 10/21/21

Ph.D. University Professor with 10+ years Tutoring Experience

molar mass (NH_{4})_{2}SO_{4} = 132 g / mol

Since we are interested only in the nitrogen (N), we want to find how much N is present in each mol of (NH_{4})_{2}SO_{4}. One mol (NH_{4})_{2}SO_{4} contains 2 mols N. The mass of N per mol of (NH_{4})_{2}SO_{4} is ...

1 mol (NH_{4})_{2}SO_{4} x 2 mol N / mol (NH_{4})_{2}SO_{4} x 14 g N / mol N = 28 g N

% N = 28 g / 132 g (x100%) = 21.2% N

1 lb N x 454 g N / lb = 454 g N required

0.212 x = 454 g

x = 2142 g (NH_{4})_{2}SO_{4} required per year

Jonah Mae Y.

thank you sir, it help me to understand this problem now.10/22/21