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An object weighs $10\ N$ in air. When immersed fully in water, it weighs only $8\ N$. The weight of the liquid displaced by the object will be
$(a).\ 2\ N$
$(b).\ 8 N$
$(c).\ 10\ N$
$(d).\ 12\ N$
Here, the weight of the object in the air $=10\ N$
Weight of the object, when immersed in water $=8\ N$
According to Archimedes' principle, the buoyant force$=$weight of the displaced liquid by the body.
Therefore, the weight of the liquid displaced by the object $=10\ N-8\ N=2\ N$
So, option $(a)$ is correct.
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