ABC is an isosceles triangle right angled at C. Prove that $AB^2 = 2AC^2$.
Given:
ABC is an isosceles triangle right angled at C.
To do:
We have to prove that $AB^2 = 2AC^2$.
Solution:
In $∆ABC$, by Pythagoras theorem,
$AB^2= BC^2 + AC^2$
$AB^2 = AC^2 + AC^2$
$= 2AC^2$
Hence proved.
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