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(a) Write a pair of negative integers whose difference gives $8$.
(b) Write a negative integer and a positive integer whose sum is $-5$.
(c) Write a negative integer and a positive integer whose difference is $-3$.
To do :
We have to write
(a) a pair of negative integers whose difference gives $8$.
(b) a negative integer and a positive integer whose sum is $-5$.
(c) a negative integer and a positive integer whose difference is $-3$.
Solution :
(a) Difference is $8$.
Let us consider $-3$ and $-11$
Difference $=-3-(-11)$
$=-3+11$
$=8$
(b) Sum is $-5$
Let us consider $4$ and $-9$
Sum $=4 + (-9) = -5$
(c) Difference is $-3$.
Let us consider $-1$ and $2$
Difference $=(-1) - (2) = -(1+2) = -3$.
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