# A truck of mass $M$ is moved under a force $F$. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?

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As given, the mass of the truck $=M$

Force applied $=F$

Then acceleration $a=\frac{F}{M}$     ........ $(i)$

If the truck is loaded with an object having a mass equal to the truck, then mass $=2M$

And the force is halved, so it becomes $\frac{F}{2}$

So, acceleration $a\'=\frac{\frac{F}{2}}{2M}$

$=\frac{F}{4M}$

$=\frac{1}{4}\times \frac{F}{M}$

$=\frac{1}{4}\times a$                [from $(i)\ a=\frac{F}{M}$]

So, acceleration $a\'=\frac{a}{4}$

Therefore, If the truck is loaded with an object equal to the mass of the truck and the driving force is halved, then the acceleration becomes one forth.

Updated on 10-Oct-2022 13:28:47