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# A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows:

**(i)** Make a grouped frequency distribution table for this data with class intervals as $ 0.00-0.04

A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city.

To do:

We have to

(i) Make a grouped frequency distribution table for this data with class intervals as \( 0.00-0.04,0.04-0.08 \), and so on.

(ii) Find the number of days on which concentration of sulphur dioxide was more than \( 0.11 \) parts per million.

Solution:

(i) The given data is large, so we construct a grouped frequency distribution table of class size 0.04.

This implies,

The class intervals are 0.00 - 0.04, 0.04 - 0.08 and so on.

The data is represented in the grouped frequency distribution table as follows:

Concentration of $SO_2$ (in ppm) | Frequency |

0.00-0.04 | 4 |

0.04-0.08 | 9 |

0.08-0.12 | 9 |

0.12-0.16 | 2 |

0.16-0.20 | 4 |

0.20-0.24 | 2 |

Total | 30 |

(ii) The number of days in which the concentration of sulphur dioxide was more than $0.11$ parts per million $= 2+4+ 2$

$= 8$

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