A student very cautiously traces the path of a ray through a glass slab for different values of the angle of incidence (i). He then measures the corresponding values of the angle of refraction (r) and the angle of emergence (e) for every value of the angle of incidence. On analyzing these measurements of angles, his conclusion would be(A) (B) $\angle i = \angle e > \angle r$ (C) $\angle i < \angle r < \angle e$ (D) $\angle i = \angle e < \angle r$"

(B) Ði = Ðe > Ðr

Explanation

Since the emergent ray is always parallel to the incident ray when a ray of light passes from a rarer medium (air) to the denser medium through (a glass slab). Therefore the angle of incidence is always equal to the angle of emergence i.e $\angle i=\angle e$ ................ (i)

Also, when a light ray travels from a rarer medium (air) to the denser medium (glass slab), it slightly bends towards the normal after refraction. Thus the angle of refraction is smaller than the angle of incidence i.e, $\angle i>\angle r$ ................ (ii) 

From (i) and (ii), we get

The angle of refraction is always less than both the other angles. So, $\angle i=\angle i>\angle r$ 

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Updated on: 10-Oct-2022

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