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A pendulum oscillates $40$ times in $4$ seconds. Find its time period and frequency.
Given:
A pendulum oscillates $40$ times in $4$ seconds.
To do:
To find its time period and frequency.
Solution:
Given that a pendulum oscillates 40 times in 4 seconds.
Number of oscillations $=40$
Total time taken $=4\ seconds$
The time period, $T=\frac{Total-time}{Number\ of\ oscillation}$
$=\frac{4}{40}$
$=0.1\ s$
We know that frequency $f=\frac{number\ of\ oscillations}{time}$
$=\frac{40}{4}$
$=10\ Hz$
Therefore, the time period of the given pendulum is $0.1\ s$ and the frequency is $4\ Hz$.
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