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A metal that exists as a liquid at room temperature is obtained by heating its sulphide in the presence of air. Identify the metal and its ore and give the reaction involved.
The metal is Mercury, Hg as it is liquid at room temperature.
Sulphide ore of mercury is Cinnabar, HgS(mercury II sulphide).
Mercury can be extracted from its sulphide ore by first roasting it in air. The equation is written as:
$2HgS + 3O_2 → 2HgO + 2 SO_2$
HgO is further heated to 300oC and gets reduced to mercury.
$2HgO→ 2Hg + O_2$
Updated on: 10-Oct-2022
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