A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement-time graph is shown in the figure. Plot a velocity-time graph for the same.
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From the given distance-time graph, 

$Velocity=\frac{displacement}{time}$

$=\frac{100}{50}$

$=2\ m/s$

In the given distance-time graph the symmetry indicates that the girl reaches back to her initial position with the same velocity$(2\ m/s)$ but in opposite direction. So, the velocity-time graph will be as below:

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Updated on: 10-Oct-2022

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