A floor is $ 5 \mathrm{~m} $ long and $ 4 \mathrm{~m} $ wide. A square carpet of sides $ 3 \mathrm{~m} $ is laid on the floor. Find the area of the floor that is not carpeted.

Given:

A floor is $5\ m$ long and $4\ m$ wide. A square carpet of sides $3\ m$ is laid on the floor. 

To do:

We have to find the area of the floor that is not carpeted.

Solutions:

We know that,

The area of a rectangle with length '$l$' and breadth '$b$' is $l \times b$.

The area of a square of side $s$ is $s^2$.

Therefore,

The area of the floor $=5\ m \times 4\ m$

$=20\ m^2$

The area of the square carpet  $=(3\ m)^2$

$=9\ m^2$

We have to subtract the area of the square from the area of the floor to get the area of the floor that is not carpeted.

The area of the floor that is not carpeted $=20\ m^2 - 9\ m^2$

$= 11\ m^2$

The area of the floor that is not carpeted is $11\ m^2$.