(a) Complete the table and by inspection of the table find the solution to the equation $ m+10=16 $

(b) Complete the table and by inspection of the table

AcademicMathematicsNCERTClass 6

To do:

We have to complete the tables and by inspection of the tables find the solutions to the equations.

Solutions:

(a) For $m + 10$, the table is represented as below:

$m$$m+10$
1$1+10=11$
2$2+10=12$
3$3+10=13$
4$4+10=14$
5$5+10=15$
6$6+10=16$
7$7+10=17$
8$8+10=18$
9$9+10=19$
10$10+10=20$

Therefore, from the table,

The solution to the equation $m+10=16$ is $m=6$.

(b) For $5t$, the table is represented as below:

$t$$5t$
3$5\times3=15$
4$5\times4=20$
5$5\times5=25$
6$5\times6=30$
7$5\times7=35$
8$5\times8=40$
9$5\times9=45$
10$5\times10=50$
11$5\times11=55$

Therefore, from the table,

The solution to the equation $5t=35$ is $t=7$.

(c) For $\frac{z}{3}$, the table is represented as below:

$z$$\frac{z}{3}$
8$\frac{8}{3}=2\frac{2}{3}$
9$\frac{9}{3}=3$
10$\frac{10}{3}=3\frac{1}{3}$
11$\frac{11}{3}=3\frac{2}{3}$
12$\frac{12}{3}=4$
13$\frac{13}{3}=4\frac{1}{3}$
14$\frac{14}{3}=4\frac{2}{3}$
15$\frac{15}{3}=5$
16$\frac{16}{3}=5\frac{1}{3}$

Therefore, from the table,

The solution to the equation $\frac{z}{3}=4$ is $z=12$.

(d) For $m-7$, the table is represented as below:

$m$$m-7$
5$5-7=-2$
6$6-7=-1$
7$7-7=0$
8$8-7=1$
9$9-7=2$
10$10-7=3$
11$11-7=4$
12$12-7=5$
13$13-7=6$
14$14-7=7$

Therefore, from the table,

The solution to the equation $m-7=3$ is $m=10$.

raja
Updated on 10-Oct-2022 13:36:49

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