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A circular flower bed is surrounded by a path $4\ m$ wide. The diameter of the flower bed is $66\ m$. What is the area of this path? $(\pi=3.14)$
Diameter of the flower bed$=66\ m$
Radius$=\frac{66}{2}=33\ m$
Width of the path$=4\ m$
The radius of the flower bed included a path
$=33\ m+4\ m=37\ m$
Let $r_2=37\ m$
Area of the circular path$=\pi\left(r_2^2-r_1^2\right)$
$=3.14\left(37^2-33^2\right)$
$=3.14\times(37+33)(37-33)$ [$a^2-b^2=(a+b)(a-b)$]
$=3.14\times70\times4=879.20\ m^2$
Hence, the required area$=879.20\ m^2$
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