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A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is
(i) red?
(ii) not red?
Given:
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag.
To do:
We have to find the probability that the ball drawn is
(i) red.
(ii) not red
Solution:
(i) Number of red balls $=3$
Number of black balls $=5$
Total number of balls $=3+5=8$
This implies,
The total number of possible outcomes $n=8$.
Total number of favourable outcomes(drawing a red ball) $=3$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability that the ball drawn is red $=\frac{3}{8}$
The probability that the ball drawn is red is $\frac{3}{8}$.
(ii) Number of red balls $=3$
Number of black balls $=5$
Total number of balls $=3+5=8$
This implies,
The total number of possible outcomes $n=8$.
Here, not a red ball implies that the ball drawn is black.
Total number of favourable outcomes(drawing a black ball) $=5$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability that the ball drawn is not red $=\frac{5}{8}$
The probability that the ball drawn is not red is $\frac{5}{8}$.
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