18 is divisible by both 2 and 3 . It is also divisible by $ 2 \times 3=6 $. Similarly, a number is divisible by both 4 and 6. Can we say that the number must also be divisible by $ 4 \times 6=24 $ ? If not, give an example to justify your answer.
Given:
18 is divisible by both 2 and 3 . It is also divisible by \( 2 \times 3=6 \). Similarly, a number is divisible by both 4 and 6.
To do :
We have to find whether the number is be divisible by \( 4 \times 6=24 \).
Solution :
It is not necessary that the number is be divisible by \( 4 \times 6=24 \).
Example:
12 and 36 are both divisible by 4 and 6.
12 and 36 are not divisible by 24.
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