PHP mysqli_dump_debug_info() Function

Definition and Usage

The mysqli_dump_debug_info() function accepts a object representing a connection to the MySQL server and, dumps the debugging information in to the log.

Syntax

mysqli_dump_debug_info($con);

Parameters

Return Values

This function returns the boolean value which is, TRUE on success and FALSE in case of failure.

PHP Version

This function was first introduced in PHP Version 5 and works works in all the later versions.

Example

Following example demonstrates the usage of the mysqli_dump_debug_info() function (in procedural style) −

<?php
   //Creating a connection
   $con = mysqli_connect("localhost", "root", "password", "mydb");
   $res = mysqli_dump_debug_info($con);

   if($res){
      print("Debugging is successful");
   }else{
      print("Failed to debug");
   }
?>

This will produce following result −

Debugging is successful

Example

<?php
   $servername = "localhost";
   $username = "root";
   $password = "password";
   $dbname = "mydb";
   $conn = new mysqli($servername, $username, $password, $dbname);

   if ($conn->connect_error) {
      die('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
   } 
   echo 'Success... ' . mysqli_get_host_info($conn)."\n";
   mysqli_dump_debug_info($conn);
   mysqli_autocommit($conn,FALSE);
   mysqli_query($conn,"INSERT INTO tutorials_auto (id,name) VALUES (10,'sai')");
   mysqli_commit($conn);
   
   mysqli_close($conn);
?>

This will produce following result −

Success... localhost via TCP/IP