Java Examples - Comparing performance


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Problem Description

How to compare performance of string creation ?

Solution

Following example compares the performance of two strings created in two different ways.

public class StringComparePerformance {
   public static void main(String[] args) {      
      long startTime = System.currentTimeMillis();
      
      for(int i=0;i<50000;i++) {
         String s1 = "hello";
         String s2 = "hello"; 
      }
      long endTime = System.currentTimeMillis();
      System.out.println("Time taken for creation" 
         + " of String literals : "+ (endTime - startTime) 
         + " milli seconds" );       
      long startTime1 = System.currentTimeMillis();
      
      for(int i=0;i<50000;i++) {
         String s3 = new String("hello");
         String s4 = new String("hello");
      }
      long endTime1 = System.currentTimeMillis();
      System.out.println("Time taken for creation" 
         + " of String objects : " + (endTime1 - startTime1)
         + " milli seconds");
   }
}

Result

The above code sample will produce the following result.The result may vary.

Time taken for creation of String literals : 0 milli seconds
Time taken for creation of String objects : 16 milli seconds

java_strings.htm

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