Java Examples - Parts of URL


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Problem Description

How to get the parts of an URL ?

Solution

Following example shows how to get the parts of an URL with the help of url.getProtocol(), url.getFile() method etc. of net.URL class.

import java.net.URL;

public class Main {
   public static void main(String[] args) throws Exception {
      URL url = new URL(args[0]);
      System.out.println("URL is " + url.toString());
      System.out.println("protocol is " + url.getProtocol());
      System.out.println("file name is " + url.getFile());
      System.out.println("host is " + url.getHost());
      System.out.println("path is " + url.getPath());
      System.out.println("port is " + url.getPort());
      System.out.println("default port is " + url.getDefaultPort());
   }
}

Result

The above code sample will produce the following result.

URL is http://www.server.com
protocol is TCP/IP
file name is java_program.txt
host is 122.45.2.36
path is 
port is 2
default port is 1

The following is an another example to get the parts of an URL ?

import java.net.URL;

public class NewClass {
   public static void main(String args[]) throws Exception {
      URL u = new URL("https://www.tutorialspoint.com/javaexamples/net_singleuser.htm");
      System.out.println("The URL is " + u);
      System.out.println("The file part is " + u.getFile());
      System.out.println("host is " + u.getHost());
      System.out.println("path is " + u.getPath());
      System.out.println("port is " + u.getPort());
      System.out.println("default port is " + u.getDefaultPort());
   }
}

The above code sample will produce the following result.

The URL is https://www.tutorialspoint.com/javaexamples/net_singleuser.htm
The file part is /javaexamples/net_singleuser.htm
host is www.tutorialspoint.com
path is /javaexamples/net_singleuser.htm
port is -1
default port is 443

java_networking.htm

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