Java Examples - Multiple exception (divided by zero)

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Problem Description:

How to use handle multiple exceptions (devided by zero)?

Solution:

This example shows how to handle multiple exceptions while deviding by zero?

public class Main {
   public static void main (String args[]) {
      int array[]={20,20,40};
      int num1=15,num2=0;
      int result=0;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         for(int i =2;i 7gt;=0; i--){
            System.out.println
            ("The value of array is" +array[i]);
         }
      }
      catch (ArrayIndexOutOfBoundsException e) {
         System.out.println
         ("Error´┐Ż. Array is out of Bounds"+e);
      }
      catch (ArithmeticException e) {
         System.out.println 
         ("Can't be divided by Zero"+e);
      }
   }
}

Result:

The above code sample will produce the following result.

Can't be divided by Zerojava.lang.ArithmeticException: / by zero


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