Java Examples - Multiple exception (divided by zero)


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Problem Description

How to use handle multiple exceptions (devided by zero) ?

Solution

This example shows how to handle multiple exceptions while deviding by zero ?

public class Main {
   public static void main (String args[]) {
      int array[] = {20,20,40};
      int num1 = 15, num2 = 0;
      int result = 0;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         
         for(int i = 2; i >=0; i--) {
            System.out.println("The value of array is" +array[i]);
         }
      } catch (ArrayIndexOutOfBoundsException e) {
         System.out.println("Error. Array is out of Bounds"+e);
      } catch (ArithmeticException e) {
         System.out.println ("Can't be divided by Zero"+e);
      }
   }
}

Result

The above code sample will produce the following result.

Can't be divided by Zerojava.lang.ArithmeticException: / by zero

The following is an another example to use handle multiple exceptions in Java.

public class JavaApplication4 { 
   public static void main(String args[]) { 
      try { 
         int a[] = new int[5];
         a[5] = 30/0;  
      }  
      catch(ArithmeticException e){System.out.println("task1 is completed");}  
      catch(ArrayIndexOutOfBoundsException e){System.out.println("task 2 completed");}  
      catch(Exception e){System.out.println("common task completed");}
      System.out.println("rest of the code...");  
   }  
} 

The above code sample will produce the following result.

task1 is completed
rest of the code...

java_exceptions.htm

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