Java.util.Scanner.hasNextLine() Method


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Description

The java.util.Scanner.hasNextLine() method returns true if there is another line in the input of this scanner. This method may block while waiting for input. The scanner does not advance past any input.

Declaration

Following is the declaration for java.util.Scanner.hasNextLine() method

public boolean hasNextLine()

Parameters

  • NA

Return Value

This method returns true if and only if this scanner has another line of input

Exception

  • IllegalStateException -- if this scanner is closed

Example

The following example shows the usage of java.util.Scanner.hasNextLine() method.

package com.tutorialspoint;

import java.util.*;

public class ScannerDemo {

   public static void main(String[] args) {

   String s = "Hello World! \n 3 + 3.0 = 6 ";

   // create a new scanner with the specified String Object
   Scanner scanner = new Scanner(s);

   // print the next line
   System.out.println("" + scanner.nextLine());

   // check if there is a next line again
   System.out.println("" + scanner.hasNextLine());

   // print the next line
   System.out.println("" + scanner.nextLine());

   // check if there is a next line again
   System.out.println("" + scanner.hasNextLine());

   // close the scanner
   scanner.close();
   }
}

Let us compile and run the above program, this will produce the following result:

Hello World! 
true
 3 + 3.0 = 6 
false

java_util_scanner.htm

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