Java.util.Arrays.sort(short[]) Method
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Description
The java.util.Arrays.sort(short[]) method sorts the specified array of shorts into ascending numerical order.
Declaration
Following is the declaration for java.util.Arrays.sort() method
public static void sort(short[] a)
Parameters
a -- This is the array to be sorted.
Return Value
This method does not return any value.
Exception
- NA
Example
The following example shows the usage of java.util.Arrays.sort() method.
package com.tutorialspoint;
import java.util.Arrays;
public class ArrayDemo {
public static void main(String[] args) {
// initializing unsorted short array
short sArr[] = {22, 10, 9, 62, 5};
// let us print all the elements available in list
for (short number : sArr) {
System.out.println("Number = " + number);
}
// sorting array
Arrays.sort(sArr);
// let us print all the elements available in list
System.out.println("The sorted short array is:");
for (short number : sArr) {
System.out.println("Number = " + number);
}
}
}
Let us compile and run the above program, this will produce the following result:
Number = 22 Number = 10 Number = 9 Number = 62 Number = 5 The sorted short array is: Number = 5 Number = 9 Number = 10 Number = 22 Number = 62