Java.util.Arrays.sort() Method

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Description

The java.util.Arrays.sort(Object[] a, int fromIndex, int toIndex) method sorts the specified range of the specified array of objects into ascending order, according to the natural ordering of its elements. The range to be sorted extends from index fromIndex, inclusive, to index toIndex, exclusive.

Declaration

Following is the declaration for java.util.Arrays.sort() method

public static void sort(Object[] a, int fromIndex, int toIndex)

Parameters

  • a -- This is the array to be sorted.

  • fromIndex -- This is the index of the first element (inclusive) to be sorted.

  • toIndex -- This is the index of the last element (exclusive) to be sorted.

Return Value

This method does not return any value.

Exception

  • IllegalArgumentException -- if fromIndex > toIndex

  • ArrayIndexOutOfBoundsException -- if fromIndex < 0 or toIndex > a.length

  • ClassCastException -- if the array contains elements that are not mutually comparable (for example, strings and integers)

Example

The following example shows the usage of java.util.Arrays.sort() method.

package com.tutorialspoint;

import java.util.Arrays;

public class ArrayDemo {

   public static void main(String[] args) {

    // initializing unsorted Object array
    Object ob[] = {27, 11, 5, 44};

    // let us print all the elements available in list
    for (Object number : ob) {
      System.out.println("Number = " + number);
    }

    // sorting array from index 1 to 3
    Arrays.sort(ob, 1, 3);

    // let us print all the elements available in list
    System.out.println("Object array with some sorted values(1 to 3) is:");
    for (Object number : ob) {
      System.out.println("Number = " + number);
    }
  }
}

Let us compile and run the above program, this will produce the following result:

Number = 27
Number = 11
Number = 5
Number = 44
Object array with some sorted values(1 to 3) is:
Number = 27
Number = 5
Number = 11
Number = 44



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